tag:blogger.com,1999:blog-28368291.post1793362612251886844..comments2023-09-13T13:19:15.216+05:30Comments on Fused Bulbs: Tough oneUnknownnoreply@blogger.comBlogger3125tag:blogger.com,1999:blog-28368291.post-14348086810868218282007-07-07T15:27:00.000+05:302007-07-07T15:27:00.000+05:30well, if the same guy gets taken in again and agai...well, if the same guy gets taken in again and again he keeps the position at 1........i shud have written "multiple timers" instead of "second timers".<BR/>and the no shud be 23 and not 22.....to cover up for the initial configuration.<BR/>i still dont see anything wrong with wat i say, except that there can be a shorter and smarter method, if u have it, go ahead....and solve itAnkit Sagwalhttps://www.blogger.com/profile/14968617934592734839noreply@blogger.comtag:blogger.com,1999:blog-28368291.post-89695877798029906192007-07-04T18:21:00.000+05:302007-07-04T18:21:00.000+05:30not necessarily, you see, the same prisoner can be...not necessarily, you see, the same prisoner can be taken in multiple times...RGhttps://www.blogger.com/profile/11177269454641034500noreply@blogger.comtag:blogger.com,1999:blog-28368291.post-63314771923156365892007-07-03T17:14:00.000+05:302007-07-03T17:14:00.000+05:30let me try this,even though i feel i am far from s...let me try this,even though i feel i am far from solving it.<BR/>How about getting two configurations, lets say on-on and on-off as category 1, and other two off-off and off-on as category 2.Now any prisoner that visits first time tries to get a category 2 configuration, which is always possible.....and second timers get 1 when they leave.<BR/>The problem of initial position is kinda solved here......but the number of tries is very large.....one prisoner has to see 22 config 1 to say that they have all visitedAnkit Sagwalhttps://www.blogger.com/profile/14968617934592734839noreply@blogger.com