### a spark of light

Ok kvpyians! I'm spidy again with a new identity. I lost my password and was unable to post. Here's another of those 1=2s. This is a sort of general one for twish's first 1=2.

(n+1)^2 = n^2 + 2n + 1

or, (n+1)^2 - (2n+1) = n^2

subtracting n(2n+1),

or, (n+1)^2 - (n+1)(2n+1) = n^2 - n(2n+1)

or, (n+1)^2 - (n+1)(2n+1) + 1/4(2n+1)^2 = n^2 - n(2n+1) + 1/4(2n+1)^2

or, (n - 1/2)^2 = (n + 1/2)^2

or, (n - 1/2) = (n + 1/2)

or, -1/2 = +1/2

or, 1 = 0

or, 2 = 1 !!

All this while we have had maths and physics discussed in our blog. I feel the time has come for the budding chemists to make us feel their presence. So an open question: what is the fundamental reason behind the optical activity of enantiomers?

LeTs SpArK oUr BuLbS!

## 3 comments:

Hi spidy!

Maybe u have made a mistake

(n+1)^2-(n+1)(2n+1)+1/4(2n+1)^2=n^2-n(2n+1)+1/4(2n+1)^2

=>(n+1-n-1/2)^2=(n-n-1/2)^2

=>(1/2)^2=(-1/2)^2

which is obvious.

Well, I reckon Sunita is rite - u can edit your post when u figure out what went wrong!

And yeah, I hav no idea about Chemistry, so don't expect any post on it from me!!

;)

BTW, i saw the same thing on web some day and the mistake u are doing is that when u cancel the squares on both sides, a + and - sign comes on both sides and not always a + sign.

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